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D( x )
x/12 < 0
x/12 < 0
x/12 < 0
1/12*x+0 < 0 // - 0
1/12*x < 0 // : 1/12
x < 0/1/12
x < 0
x in <0:+oo)
7 = (x/12)^(1/20)-1 // - (x/12)^(1/20)-1
1-(x/12)^(1/20)+7 = 0
-(1/12)^(1/20)*x^(1/20) = -8 // : -(1/12)^(1/20)
x^(1/20) = 8/((1/12)^(1/20))
( 8/((1/12)^(1/20)) < 0 i 1/20 in (0:1) ) => x należy do O
x belongs to the empty set
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